You have .07 liters of 1.46 M H2SO4 so that means you have .07*1.46=.1022 moles of H2SO4. Because the stoichiometric ratio of H2SO4 to Ca(OH)2 the same amount of Ca(OH)2 is required to neutralize the H2SO4 as you have moles of H2SO4. So, .1022 moles are required to neutralize and you need grams and the molecular weight of Ca(OH)2 is 74.1 you have .1022*74.1=7.57 grams of Ca(OH)2 required to neutralize the H2SO4
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